Calculate the number of oxygen atoms present in 11.2 litres of oxygen gas
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11.2 lit is 0.5 mole
therefore, no of atoms= 12.046*10^23/2= 6.023*10^23 oxygen atoms
all the best
therefore, no of atoms= 12.046*10^23/2= 6.023*10^23 oxygen atoms
all the best
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