Question

Calculate the number of oxygen atoms present in 2.5 moles of Nitric acid.
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Answer 1

Explanation:

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Answer 2

\bold{\huge{= \underline{3.6 \times 10^{24}\:atoms}}}

= 36.12 × 10²³ or approx

= 12.04 × 3 × 10²³ atoms

Then 3 atoms of hydrogen will have

= 12.04 × 10²³ atoms

2 mole will have = 6.022 × 2 × 10²³ atoms

Since 1 mole have = 6.022 × 10²³ atoms

, there are 3 atoms of Oxygen.

\Longrightarrow{\boxed{\bold{Answer:3.6 \times 10^{24}\:atoms }}}