Question

calculate the number of oxygen ions and oxygen ions present in 0.051 grams of Aluminium oxide​

Answer 1

Answer:

the no of

Step-by-step explanation:

use the given set of eg

Answer 2

Mark in brainliest

Answer :

• 1 mole of Aluminium Oxide (Al2O3) = 2 × 27 + 3 × 16 = 102 g. ...
• We know, The number of atoms present in given mass = (Given mass ÷ molar mass) × Avogadro number.
• Then, 0.051 g of Aluminium Oxide (Al2O3) contains.
• = (0.051 ÷ 102 ) × 6.022 × 1023 molecules of Aluminium Oxide