Calculate the number of particles-(i) 87grams of sulphur atoms (ii) 0.34 moles of Nitrogen molecule.
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Answer:
(i) 16.37 × 6.022 × 10²³ atoms
(ii) 2.047 × 10²³ molecules
Explanation:
Using concept :
Number of particles in 1 mole of any species = Avogadro's number = 6.022 × 10²³
(i) Molar mass of Sulphur = 32 g
32 g of Sulphur contains = 6.022 × 10²³ atoms
1 g of Sulphur contains = (1/32) × 6.022 × 10²³ atoms
87 g of Sulphur contains = (1/32) × 87 × 6.022 × 10²³ atoms
87 g of Sulphur contains = 16.37 × 6.022 × 10²³ atoms
Thus, 87 g of Sulphur contains 16.37 × 6.022 × 10²³ atoms.
(ii) 1 mole of Nitrogen molecule = 6.022 × 10²³ molecules
0.34 moles of Nitrogen molecule = 0.34 × 6.022 × 10²³ molecules
0.34 moles of Nitrogen molecule = 2.047 × 10²³ molecules
Thus, 0.34 moles of Nitrogen contains 2.047 × 10²³ molecules.
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