Calculate the number of particles in 23 g of Na atoms
Answers
Answer:
frist we have to divide mass of Na w.r.t molar mass of Na. #) molar mass of Na =23 gm/mol. #) no of moles of Na =46/23. =2mol.
than we easily get the no of moless. no of atoms in Na =2 * avocadro no= 2 * 6.03 *10^23=12.06 *10^23 atom.
than we have to multiply the no of moless wd avocadro no.
Answer:
☑️☑️ first we have to divide mass of Na w.r.t molar mass of Na. #) molar mass of Na =23 gm/mol. #) no of moles of Na =46/23. =2mol.
☑️☑️ than we easily get the no of moless. no of atoms in Na =2 * avocadro no= 2 * 6.03 *10^23 =12.06 *10^23 atom
☑️☑️ than we have to multiply the no of moless wd avocadro no.
Explanation:
There are 6.02*10^23 atoms in each mole (Avagadro no.) That is x moles * avagadro no. According to that, in 23 grams of sodium we have 6.02*10^23 atoms of Na
⤴️⤴️⤴️⤴️⤴️⤴️⤴️⤴️
hope it helps you ❇️