Question

Calculate the number of particles in 40 g of calcium and 100 g If ferrous which is heavier

Answer 1

Answer: There will be $6.022\times10^{23}$ particles of Calcium and $10.783\times20^{23}$ paricles of Ferrous.

Explanation: We are given 40g of Calcium and 100g of Ferrous.

To calculate the number of particles, we multiply the moles with Avogadro's Number.

$\text{Number of particles}=\text{Avogadro's Number}\times \text{Moles}$

Moles are calculated as,

$\text{Moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Number of particles become,

$\text{Number of particles}=\text{Avogadro's Number}\times \frac{\text{Given mass}}{\text{Molar mass}}$

Taking 40g of Ca,

Given mass = 40g

Molar Mass = 40g/mol (From periodic table)

$\text{Number of particles}=\frac{(6.022\times 10^{23}particles/mol)(40g)}{40g/mol}$

$\text{Number of particles}=6.022\times10^{23}\text{ particles of Calcium}$

Now taking 100g of Ferrous,

Given mass = 100g

Molar mass = 55.845g/mol ( From periodic table)

$\text{Number of particles}=\frac{(6.022\times 10^{23}particles/mol)(100g)}{55.845g/mol}$

$\text{Number of particles}=10.783\times10^{23}\text{ particles of Ferrous}$