Question

calculate the number of particles in 64g of methane
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Answer 1

Answer:CH4 molecule contains 1 carbon atom and 4 hydrogen atom.

Now, carbon atom contains 6 e, and hydrogen atom contains 1e each. So there are 6 + (1*4) = 10 e in methane molecule. [4 for hydrogen atom]

Now, molecular weight of methane is 16gm or you may say it is the weight of 6.022 * 10^23 molecules of methane.

Now, no. of moles of methane = Given mass/molar mass = 64/16 = 4.

So, there are 4 moles of methane or 4* 6.022 * 10^23 molecules of methane [ one mole has weight as molecular weight in gm] or 10 * 4 * 6.022 *10^23 e in 64 gm of methane [as each molecule has 10e].

:)

Explanation:

Answer 2

Explanation:

Atomic mass of C is 12u and of H is 1u

There are 4 H atoms and 1 C atom.

Thus the molecular mass of CH4 is 12+1∗4=16u=16g/mol12+1∗4=16u=16g/mol

Now, 1 C atom contains 6 e−e−

and 1 H contains 1 e−e−

Total no. of electrons in 1 molecule of CH4=6+4=10

No. of moles in 64g CH4 is 64/16=4

In one mole CH4 there are 6.023*10231023

molecules.Each molecule contains 10 electrons.

Therefore no. of electrons in in 4 moles of CH4=4*10*6.023*10^23 electrons

Therefore there are 240.92*10231023electrons in 64 g CH4

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