Question

Calculate the number of particles in 92 g of sodium atoms.
[Atomic mass of Na – 23u]

Answer 1

Answer:

24×10^23 particles

Explanation:

No. of particles = n × 6.023×10^23

where, n = Given mass ÷ molar mass of the atom (moles)

So,

No. of particles = 92÷23 × 6.023× 10^23

= 4 × 6.023× 10^23

= 24 × 10^23 particles

Answer 2

Given: 92 grams of Na atom.

To find: We have to find the number of particles.

Solution:

The number of particles of 92g of Na atom can be determined by the below steps-

Na is an alkali metal. It has an atomic number of 11 and an atomic mass of 23u.

23g of Na atom contains $6.023×10^{23}$ number of particles.

Thus 92g of Na atom contains $6.023×10^{23}×92/23=24.092×10^{23}$ number of particles.

Thus 92g of Na atom contains $24.092×10^{23}$ number of particles.