calculate the number of particles in (a) 46 g of Na atom(b) 8 g of O2 moles(c) 0.1 moles of carbon atom
KaasiniMohan:
is it using empirical formula method
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1) Atomic mass of Na is 23
46÷23 = 2 moles
1 mole = 6.02 × 10²³
2×6.02×10²³ = 1.2 × 10*24
2) Atomic mass of o2 is 32
8÷32 = 0.25 moles
0.25×6.02×10²³= 1.51 × 10²³
3) 0.1 ×6.02×10²³= 6.02 ×10²³
46÷23 = 2 moles
1 mole = 6.02 × 10²³
2×6.02×10²³ = 1.2 × 10*24
2) Atomic mass of o2 is 32
8÷32 = 0.25 moles
0.25×6.02×10²³= 1.51 × 10²³
3) 0.1 ×6.02×10²³= 6.02 ×10²³
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Answer:
1) Atomic mass of Na is 23
46÷23 = 2 moles
1 mole = 6.02 × 10²³
2×6.02×10²³ = 1.2 × 10*24
2) Atomic mass of o2 is 32
8÷32 = 0.25 moles
0.25×6.02×10²³= 1.51 × 10²³
3) 0.1 ×6.02×10²³= 6.02 ×10²³
Explanation
hope it help you
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