Question

calculate the number of particles in each of the following: i) 46 grams of Na atoms (NUMBER FROM MASS) ii) 8 grams of O2molecules (NUMBER OF MOLECULE FROM MASS) iii) 0.1 mole of carbon atoms (NUMBER OF GIVEN MOLES)

Answer 1

1)no of particle=A(46/23)=2A
where A is avogadro constant
2) no of molecule=A (8/32)=.25A
no of particle=2.(.25A)=.5A
3) no of particle=.1A

Answer 2

i ) 1 mole of Na atom contains = 6.022 x 10^{23} atoms

   46 gram of Na Atoms will contain = $\frac{6.022 * 10^{23} * 46}{23}$

                                                            =  $12.044 * 10^{23}$   Atoms

                                                                   

 

ii) 1 mole of $O_{2}$ molecule contains = 6.022 x 10^{23} atoms

   8 gram of $O_{2}$  molecules will contain = $6.022 * 10^{23} * \frac{8}{32}$  

                                                                     = $1.5055 * 10^{23}$ molecules

iii) 1 mol of carbon atom contains = 6.022 * 10^{23} atoms

   0.1 mole of carbon atom contain =  $6.022 * 10^{23} * 0.1$

                                                             = $6.022 * 10^{22}$  Atoms

$Hope-it-helps^{u}$