Question

calculate the number of particles in the following 46 gram of sodium atom and 8 gram of oxygen molecule​

Answer 1

Explanation:

For Na(Sodium) ,

n = given weight/atomic weight

= 46/23

= 2

So no of particles will be

2×Na

2× 6.022×10^(23)

12.044×10^(23)

For Oxygen,

(we consider oxygen molecule)

n = given weight /atomic weight

= 8/32

= 1/4

= 0.25

No of particles will be =>

0.25 × 6.022×10^(23)

1.5055×10^(23)

Hope it helps uh !!