Question

Calculate the number of particles of Magnesium oxide present in 20

grams of the compound.

(Given, the atomic mass of Magnesium = 24u and oxygen=16u) ​

Answer 1

Answer:

20g of MgO contains 0.5 moles.

Step-by-step explanation:

Given:

Amount of MgO, w = 20g

Molar mass of MgO, M = (24 + 16)g mol⁻¹ = 40g mol⁻¹

To find:

No. of moles of MgO in 20g, n = ?

We know that,

No. of moles = $\frac{given mass(w)}{molar mass(M)}$

∴ no. of moles in 20g of MgO, n = $\frac{20g}{40 gmol^{-1} }$

⇒ n = 0.5 mol