calculate the number of particles present in 17.75g of HCl
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Answered by
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No of particles = moles x avagadro number
molar mass of HCL = 1x1+35.5x1 = 36.5
given mass = 17.75 g
moles = 17.75/36.5 = 0.48 moles
particles = 0.48 x 6.022 x
= 2.89 x 10^23
molar mass of HCL = 1x1+35.5x1 = 36.5
given mass = 17.75 g
moles = 17.75/36.5 = 0.48 moles
particles = 0.48 x 6.022 x
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Answered by
0
Answer :-
3.011 × 10²³
Explanation :-
Given mass :- 17.75 gm
Hydrochloric acid = HCl
molecular mass = (1 + 35.5) = 36.5
= given mass / molar mass × avogrado no .
= 17.75/36.5 × 6.022 × 10²³
= 0.48 × 6.022 × 10²³ = 0.5 × 6.022 × 10²³
= 3.011 × 10²³ by round
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