calculate the number of particles present in 28g of nitrogen molecule
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sharmautkarsh1310
Secondary School Chemistry 5+3 pts
How many moles are present in 28g of nitrogen atoms?
Report by Benitamerin29 21.03.2016
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MisterMeow
MisterMeowVirtuoso
1 mole of Nitrogen is 14 grams
No. of moles present in 28g will be \frac{28}{14}=2 moles
since 1 mole of nitrogen contains 6.022* 10^{23} atoms
∴ 2 moles of Nitrogen have 6.022* 10^{23} *2 = 12.044* 10^{23} atoms
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MisterMeow
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benitamerin29
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MindfulmaiselAce
2 moles of { N }_{ 2 } are present in 28 g/mol of nitrogen.
Mole can be defined as the "number" of carbon atoms present in exactly "12 grams" of pure Carbon.
One mole of any molecule consists 6.022\quad \times \quad { 10 }^{ 23 } molecules.
Hence,
Molecular mass of nitrogen = 28 g = 1 mole
28 grams of nitrogen contains 6.022\quad \times { 10 }^{ 23 } molecules\quad of\quad { N }_{ 2 }
Each nitrogen molecule ({ N }_{ 2 }) has two nitrogen atom.
Explanation:
Answer:
2
Explanation:
mass of mole of N = 28g
We know that
one mole of particles of N = 6.022*10p23
one mole of N ,= 14u
No. of mole (n) = Given mass / Molar mass
= 28g/14g
= 2