Chemistry, asked by sweny, 4 months ago

Calculate the number of partricles in each of the following .

(a) 46 g of Na atoms ( number from mass )
(b) 8 g O2 molecules ( number of molecules from mass )

Answers

Answered by suhanijaiswal1301
1

Answer:

The given mass of sodium is 46g. ∴ The number of particles present in 46g of Na atom is 12.046×1023. Given data contains 8gO2 molecules (number of the molecules form the mass). ... Given data contains 0.1 mole of carbon atom (number form gives moles).

Answered by EuphoricBunny
16

☘️ Solution :

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(a) The number of atoms

=    \sf  \:  \dfrac{ \: given \:  \:  mass \:  }{ \:molar  \:  \: mass}  \times Avogadro \:  \:  number \\  \\  \sf \: ⟹ N \:  =  \:  \frac{m}{M}  \times N \: _0 \\  \\  \sf \: ⟹N \:  =  \: \frac{46}{23}  \times 6.022 \times 10 {}^{23 }  \\  \\  \sf \: ⟹N \:  =  \: 12.044 \times 10  {}^{23} \\ \\ \\ \\

(b) The number of molecules

=    \sf  \:  \dfrac{ \: given \:  \:  mass \:  }{ \:molar  \:  \: mass}  \times Avogadro \:  \:  number \\  \\  \sf \: ⟹ N \:  =  \:  \frac{m}{M}  \times N \: _0 \\  \\

atomic mass of oxygen = 16 u

\\

 \therefore molar mass of  \sf O_2 molecules

= 16 × 2 = 32g

\\ \\

⟹ \sf \:N~=~ \dfrac{8}{32}  \times 6.022 \times 10 {}^{23} \\   \\⟹ \sf \:N~=~ 1.5055×10²³\\ \\  \sf = 1.51 \times 10 {}^{23}

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