Question

Calculate the number of photons emitted per second by a 60W lamp, if the energy

of each photon is 3 x 10−19 ​

Answer 1

Answer:

Solution :

<br>

, <br> % used to convert into photon <br>

<br>

= hc/ lambda

= 6.63 xx 10^(-34) xx 3 xx 10^(8) / 590 xx 10^(-9)

= 6.63 xx 3 / 590 xx 10^(-17)

= ((6) / (6.63 xx 3 / 590) xx (10^(-9)))

= 6 xx 590 / 6.63 xx 3 xx 10^(17) xx 10^(19)