Calculate the number of photons of light of wavelength 3960 ampere necessary to
provide 1 joule of energy?
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Answer:
Given: The wavelength is 3960 A. The energy is 1 J.
To find; The number of photons of light in the wavelength.
Solution: The formula for the number of photons be. N= E×λ/h×c. Putting the above values. N=1J×3960×10⁻¹⁰/(6.26×10⁻³⁴)×3×10⁸ N=210.86×10¹⁶ Therefore the number of photons be 210 ×10¹⁶
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