Question

Calculate the number of Potassium ions in 7.45g of KCl? (Atomic mass of K=39u, Cl=35.5u)​

Answer 1

Answer:

Explanation:

N = n × NA

  = (wt./ mw.) ×NA

   = (7.45/74.5) × 6.023×10^23

   = .1× 6.023×10^23

  = 6.023×10^22

 no. of K+ ions will be equal to 6.023×10^23

because every KCl molecule releases one k+ ion on dissociation.