Question

Calculate the number of protons neutrons and electron in$\binom {80}{35}Br$​

Answer 1

Explanation:

in this case

• Z=35
• A=80

$\boxed{\sf Number\:of\:pRotons=Number\:of\:electrons}$

$\\ \rm{:}\longrightarrow 35$

$\\ \rm{:}\longrightarrow Number\:of\:neutrons=80-35=45$

Answer 2

$\huge\tt{\bold{\purple{\underbrace{\red{\mathfrak{Answer♡༄}}}}}}$

$Atomic \: number \longrightarrow z+35 \\ \\ </p><p></p><p> \implies \: Mass \: number \longrightarrow80 \\ \\ </p><p></p><p> \implies \:No. \: of \: proton \:  p \longrightarrow35 \\ \\ </p><p></p><p> \implies \:No. \: of \: neutron \:  n \longrightarrow80−35 \\ \\ \implies \: No. \: of \: neutron  \: n \longrightarrow45 \\ \\ </p><p></p><p> \implies \:No. \: of \: electron \:  e \longrightarrow35 \\ \\ \\ \boxed{ \pink{No. \: of \: electron \:  e = 35}}</p><p>\\ \\ \boxed{ \green{No. \: of \: electron \:  n = 45}}</p><p>\\ \\ \boxed{ \red{No. \: of \: electron \:  p = 35}}$

NOTE:-

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