Question

Calculate the number of recessive alleles in a Hardy Weinberg population of 200 individuals ,if the frequency of dominant alleles is 0.7
a.36
b.400
c.120
d.182​

Answer 1

400 is the answer of your questions

Answer 2

60 will be the number of recessive alleles

Explanation:

• We know that the frequency of the dominant allele is p = 0.7
• Now according to Hardy Weinberg equilibrium , frequency of recessive allele(q) will be ,

         q = 1-p = 1- 0.7

            = 0.3                       ( p+q = 1)

• This means that 30% of the population will have recessive alleles.
• Given that , total population is 200, 30% of 200 will be:

      $\frac{30}{100}\times 200 = 60$

• Therefore number of recessive alleles in the population will be 60.