Calculate the number of sides of a regular polygon if ,
(i) its interior angle is five times its exterior angle
(ii) the ratio between its exterior angle and interior angle is 2 : 7
(iii) its exterior angle exceeds its interior angle by 60°
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Answer:
Let number of sides of a regular polygon = n
(i) Let exterior angle = x
Then interior angle = 5x
x + 5x = 180°
=> 6x = 180°
⇒ x = 180°/6 = 30°
∴ Number of sides (n) = 360°/30° = 12
(ii) Ratio between exterior angle an interior angle = 2 : 7
Let exterior angle = 2x
Then interior angle = 7x
∴ 2x + 7x = 180°
⇒ 9x = 180°
⇒ x = 180°/9 = 20°
∴ Ext. angle = 2x = 2 × 20° = 40°
∴ No. of sides = 360°/40° = 9
(iii) Let interior angle = x
Then exterior angle = x + 60
∴ x + x + 60° = 180°
⇒ 2x = 180° - 60 = 120° ⇒ x = 120°/2 = 60°
∴ Exterior angle = 60° + 60° = 120°
∴ Number of Sides = 360°/120° = 3
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