Calculate the number of sodium atoms present in 31g of sodium oxide (NaO). Given that the atomic mass of sodium is 23u and oxygen is 16u
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2
Answer:
B) 10 moles
Sodium Oxide is Na
2
O
Molecular Weight = 46+16 = 62
62g of Na
2
O = 1 mole
620g of Na
2
O = 10 moles
Explanation:
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0
Answer:
mole concept should be used here...
31/39 = 0.79
no. of molecules = Na*n = 0.79Na
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