calculate the number of sodium ions present in 20g of Sodium sulphate solution
Answers
Explanation:
Sodium sulfate is
N
a
2
S
O
4
First, calculate the moles of sodium sulfate you have in a 14.2g sample.
Find the molar mass of sodium sulfate
molar mass = atomic mass in grams
2(23) + 32 + 4(16) = 142 grams per mole
Divide the mass of the sample by the molar mass to obtain moles
14.2
g
142
g
m
o
l
−
1
= 0.1 mol
Now, for every 1 mol of
N
a
2
S
O
4
you have 2 moles of
N
a
+
ions. Multiple the moles of
N
a
2
S
O
4
that you found just then by 2 to obtain the moles of sodium ions.
Use Avogadro's number (6.022 x
10
23
) to find the number of ions present. (Recall that Avogrado's number is the number of particles per mole of a substance).
6.022 x
10
23
x 0.2 mol = 1.2044 x
10
23
ions
Explanation:
we have the formula as well as the mass in grams so we can find mole or formula unit of the ion . then we can find number of ions from the formula unit
