Question

Calculate the number of Sodium ions present in 53 g of Sodium Carbonate .​

Answer 1

Answer:

1. 53 g of Na2CO3 Contain = 53106=12 mol.

2. No of atoms of Na = 12×2×6.022×1023= 6.022×1023.

3. No of atoms of C = 12×6.022×1023.

4. No of atoms of O =12×3×6.022×1023=9.033×1023.