Question

Calculate the number of sodium ions that are present in 212g of sodium carbonate.

With explanation​

Answer 1

Answer:

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Calculate the number of sodium ions that are present in 212g of sodium carbonate? Answer is 2.4092×10²⁴

Answer 2

Answer:

To find no of atoms present in a molecule, use the concept of atomicity.

no of atoms =atomicity×no of molecules ____(1)

step 1. find atomicity

atomicity of na ions in na2co3 =2

step 2. find no of molecules

as, 6.02×10²³ molecules= molar mass of that compound

molar mass of na2co3=(2×23)+(1×12)+(3×16) = 106g

then, 6.02×10²³ molecules=106g na2co3

for 212 g,

both sides×2,

212g of na2co3=12.04×10²³ molecules

from (1)_____ no of atoms of na in na2co3 is

2×12.04×10²³ atoms

= 24.08 ×10²³ atoms✌️✌️✌️✌️✌️