Question

Calculate the number of sulphur atom in 3.2 gram of s8

Answer 1

now only calculation is remaining that is
7.527×10^21

Answer 2

The number of sulfur atoms in given amount of $S_8$ is $4.818\times 10^{23}$

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of sulfur = 3.2 g

Molar mass of sulfur = 32 g/mol

Putting values in above equation, we get:

$\text{Moles of sulfur}=\frac{3.2g}{32g/mol}=0.1mol$

1 molecule of $S_8$ contains 8 moles of sulfur atom

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of particles

So, 0.1 mole of a molecule will contain = $(8\times 0.1\times 6.022\times 10^{23})=4.818\times 10^{23}$ number of sulfur atoms

Learn more about mole concept:

https://brainly.in/question/6813757

https://brainly.in/question/10668943

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