Chemistry, asked by Anonymous, 5 months ago

Calculate the number of the constituent atoms in 53g of Na2CO3.

Answers

Answered by HoneySparky

2

53 g of Na2CO3 Contain = 53106=12 mol.
No of atoms of Na = 12×2×6.022×1023= 6.022×1023.
No of atoms of C = 12×6.022×1023.
No of atoms of O = 12×3×6.022×1023= 9.033×1023.

Previous Question

Next Question

Similar questions

English, 2 months ago

(घ) बांस को बूढा कब कहा जा सकता है?

English, 2 months ago

use the correct form of the tense riya _____ fluent english (options) speaks speak speaking none of these...

English, 2 months ago

Fill in the blanks with suitable prepositions. [5x1=5] is we went swimming, lunch 1666, a great fire broke out in London. af The post office is the temple. W' I request you to think the matter again Rohan is sitting his mother in the parety.

Math, 5 months ago

For certain simultaneous equations, if D = -6, DX = 24, Dy = -42. Find values of x and y.

Math, 5 months ago

3. Migam bought an iron for 1200. He spent 40 for transportation. At what price he should sell it to get a profit of 25%.

English, 10 months ago

Essay on should plastic bags be banned...

Social Sciences, 10 months ago

Essay on ration shop how it works...

Economy, 10 months ago

Which of the following is not a feature of self help groups. (A) It consists of 15 -20 members or more (B) Here members pool their savings which act as collateral. (C) loans are given at nominal rate of interest. (D) It is a informal source of credit.