Question

Calculate the number of the constituent atoms in 53g of Na2CO3.

Answer 1

• 53 g of Na2CO3 Contain = 53106=12 mol.
• No of atoms of Na = 12×2×6.022×1023= 6.022×1023.
• No of atoms of C = 12×6.022×1023.
• No of atoms of O = 12×3×6.022×1023= 9.033×1023.