Calculate the number of the moles of the following 7.8g of calcium carbonate
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hoops
sorry I didn't no the answers
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Given 3.2g CaO
atomic mass = 40+16
=56
moles of Ca ion = 563.2
=0.057
1 mol = 6.022×1023 atoms of Ca ion
0.057mol=3.44×1022 Ca ions
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