Question

Calculate the number of unit cells in 0.3 g of a species having density of 8.5 g/cm3
and unit cell edge length
3.25×10-8
cm. (Ans:1.03×1021)

Answer 1

We have to find the number of unit cells in 0.3 g of a species having density of 8.5 g/cm³ and unit cell edge length 3.25 × 10^-8 cm.

solution : using formula,

n = m/ρa³

where n is the number of unit cells , m is mass of species , d is density and a is edge length of unit cell.

here m = 0.3 g

ρ = 8.5 g/cm³

a = 3.25 × 10^-8 cm

so, n = 0.3/{8.5 × (3.25 × 10^-8)³}

= 1.03 × 10²¹

Therefore the number of unit cells would be 1.03 × 10²¹

also read similar questions : The density of a fcc element(atomic mass 60.2) is 6.25 g/cm3. Calculate the edge length of the unit cell *

https://brainly.in/question/19258094

An element ( atomic mass =60 )having fcc crystal has a density of 6.23 g per cm3 . What is the edge length of unit cell

https://brainly.in/question/9297435