Question

calculate the number of valence electron present in 5.6 liters of a SO2 gas

Answer 1

Answer:

5.6 L is occupied by 0.25 moles of a gas, which will therefore contain 0.25 x 6.023 x 10^23 particles. 1.50575 * 10^23 molecules of Oxygen gas in 5.6 L. One molecule contains 2 atoms of oxygen, so the number of atoms is double the number of molecules.

Explanation: