Question

calculate the number of water molecule present in one drop of water which weighs 0.18g​

Answer 1

Answer:

First,find the number of moles:

First,find the number of moles: for that, apply the relation between mass and number of moles (n=m/M) while n is the number of moles and M is the molar mass of the entity.

First,find the number of moles: for that, apply the relation between mass and number of moles (n=m/M) while n is the number of moles and M is the molar mass of the entity. The molar mass of water (H2O) is 18g/mol (M (O) =16. M (H )=1).

First,find the number of moles: for that, apply the relation between mass and number of moles (n=m/M) while n is the number of moles and M is the molar mass of the entity. The molar mass of water (H2O) is 18g/mol (M (O) =16. M (H )=1). So the number of moles in this drop of water is 0.01mol.

First,find the number of moles: for that, apply the relation between mass and number of moles (n=m/M) while n is the number of moles and M is the molar mass of the entity. The molar mass of water (H2O) is 18g/mol (M (O) =16. M (H )=1). So the number of moles in this drop of water is 0.01mol. To find the number of molecules in this drop of water you multiply the number of moles that is 0.01 by the Avogadro constant is known as NA=6.02*10^23.

First,find the number of moles: for that, apply the relation between mass and number of moles (n=m/M) while n is the number of moles and M is the molar mass of the entity. The molar mass of water (H2O) is 18g/mol (M (O) =16. M (H )=1). So the number of moles in this drop of water is 0.01mol. To find the number of molecules in this drop of water you multiply the number of moles that is 0.01 by the Avogadro constant is known as NA=6.02*10^23. So that makes 6.02*10^21 molecules of water

Explanation:

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Answer 2

Answer:

$Molecular\: mass \: of HO=18g=1mole</p><p></p><p>$

$18g of \: water \: contains 6.022×10 {}^{23}  molecules.$

$0.18g of \: water \: contains, =$

$\dfrac{0.18 \times 6 .023 \times 10 {}^{23} }{18}$

$= 0.06023×10 {}^{23} </p><p>$

$= 6.023 \times 10 {}^{23}$

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