Question

calculate the number of water molecules in a drop of water weighing 0.05g . If the drop evaporates in one hour, how many water molecules leave the liquid surface in one second​

Answer 1

Answer:

Ans c.

1 mole of a substance contains 6.022 x 10^23 entities

To calculate how much of a substance contains one mole you determine its molecular weigh in grams

Water = H2O

Hydrogen has a molecular weight of 1; Oxygen has a moleculare weight of 16

The Moleculare weight of water (H2O) is = (2 x 1) +16 = 18

Therefore, 18 g of water will contain 6.022 x 10^23 molecules of water

Therefore

1g contains 6.022 x 10^23/18 molecules of water

Therefore,

0.05 g contains (0.05 x 6.022 x 10^23)/18 molecules of water

If his number evaporates in one hour then only 1/3600 wil evaporate per second (60min x 60 sec)

Number of water molecules evaporating per second will be:-

No. of water molecules leaving per second = 0.05 x 6.022 x 10^23)/(3600 x 18)

No. of water molecules leaving per second = 4.647 x 10^17

Explanation:

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Answer 2

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