Question

Calculate the number of water molecules present in 0.02 mole of blue vitriol (CuSO45H2O)?
ANSWER THIS I WILL MARK AS BRAINLIEST ANSWER​

Answer 1

Answer:

number of water molecules present in 0.02 mole of blue vitriol is:

12.044×10^21

Answer 2

Answer:6x 10^22

1 mole is = 5(6.022 x 10^23)

0.2 = ?