Question

Calculate the number of water molecules present in 1.8Kg of water​

Answer 1

Answer:

It is equal to Avogadro's number (NA), namely 6.022 x1023. If we have one mole of water, then we know that it will have a mass of 2 grams (for 2 moles of H atoms) + 16 grams (for one mole O atom) = 18 grams. Since we only have 0.001 grams, that means that we have NA * (0.001/18) = 3.35*1019 molecules of water!

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Answer 2

Explanation:

1.8g of water

1 mole of water =18gmol−1 18g of water contain 6.023×1023 molwcules of water

1.8g of water contains =1.8×6.023×102318

=0.602×1023

=6.02×1023

Molecules of water

1.8 gram of water will contain 0.1×6.023×1023 number of molecules. From the above discussion it's clear that the number of water molecules is maximum in 18 moles of water.