Question

calculate the number of water molecules present in one dro of water which weighs 0.18 g ​

Answer 1

Answer:

Bhai weight measure device par check kar lo

Answer 2

Hi mate

Question

Calculate the number of water molecules present in one drop of water which weights 0.18g.

Solution

Mass of water = 0.18g

$No \: Of \: Mole = Mass \div Molar \: Mass$

= 0.18/18

= 0.01 Mole

$No.of.molecules = No.of.Moles × Avagadros Number$

= 0.01 × 6.023 × 10²³

= 0.06023 ×10²³

= 6.023 × 10²¹

Therefore, 6.023 × 10²¹ molecules is your answer.

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