calculate the number particles present in 56 gm of N2 molecules
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56/14(mass of n2) =4 particles ans
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Hellooo
molar mass, that is the mass of one mole of N2 gas is 28g. One mole of any substance contains 6.023 X 1023 particles. Hence, there are 6.023 X 1023 molecules of N2 in 28g of N2. Thus
28 g of N2 = 6.023 X 1023 molecules of N2
1 g of N2 = (6.023 X 1023 / 28) molecules of N2
So 56 g of N2 = [(6.023 X 1023 X 56) / 28] molecules of N2
= 12.046 X 10²³ molecules of N2.
molar mass, that is the mass of one mole of N2 gas is 28g. One mole of any substance contains 6.023 X 1023 particles. Hence, there are 6.023 X 1023 molecules of N2 in 28g of N2. Thus
28 g of N2 = 6.023 X 1023 molecules of N2
1 g of N2 = (6.023 X 1023 / 28) molecules of N2
So 56 g of N2 = [(6.023 X 1023 X 56) / 28] molecules of N2
= 12.046 X 10²³ molecules of N2.
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