Calculate the numbers of atom of constituent elements in 53g of Na2Co3
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formula mass of Na2Co3
2×23+ 12+ 3×10
= 46+12+48= 106 amu
gram formula mass of Na2Co3 =106g
now 10g of Na2Co3
=(6.023× 10 ²³ )•/•106×5.3
=3.01×10²²
no of atoms in 5.3gof Na2Co3
2×3.01×10²²
no of Caron atoms in 5.3g of Na2Co3
=1×3.01 × 10²²
=3.01 ×10²²
no of oxygen atoms in 5.3g of Na2Co3
=3×3.01×10²²
=9.03×10²²
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