Question

calculate the numbers of moleclues in:
I)4g of CH
⁴
II)90g of H O
²
(mass of hydrogen=1,Carbon=12,Oxygen=16 and Avagadro's constant,Na=6.022x10²³​

Answer 1

Answer:

One mole of oxygen atoms contains 6.02214179×1023 oxygen atoms. Also, one mole of nitrogen atoms contains 6.02214179×1023 nitrogen atoms. The number 6.02214179×1023 is called Avogadro's number (NA) or Avogadro's constant, after the 19th century scientist Amedeo Avogadro.

Each carbon-12 atom weighs about 1.99265×10−23g; therefore,

(1.99265×10−23g)×(6.02214179×1023