calculate the numbers of moles in 1.51*10^23molecules of NH4Cl
Answers
Answered by
3
Answer:
1/4 MOLES.
Explanation:
NO. OF MOLECULES OF NH4Cl = 1.51 X 10^23 MOLECULES.
AVOGADRO NUMBER= 6.02 X 10^23 MOLECULES.
SO NO. OF MOLES OF NH4Cl= GIVEN MOLECULES / AVOGADRO NUMBER
= 1.51X10^23 / 6.02X10^23= 0.25 MOLES = 1/4 MOLES
Answered by
1
Answer:
0.25 moles
Explanation:
Atomic weight of NH4CL= (14*1)+(1*4)+(35.5*1)
= 53.5 a.m.u
So, we know that 53.5 gram = 1 mole
And, 6.023 molecules of NH4CL= 1 mole
So, 1.51*10^23 molecules= (1.51*10^23)/(6.023*10^23)=0.25 moles
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