Chemistry, asked by uma17ragu, 9 months ago

calculate the numbers of moles in 1.51*10^23molecules of NH4Cl

Answers

Answered by Anonymous
3

Answer:

1/4 MOLES.

Explanation:

NO. OF MOLECULES OF NH4Cl = 1.51 X 10^23 MOLECULES.

AVOGADRO NUMBER= 6.02 X 10^23 MOLECULES.

SO NO. OF MOLES OF NH4Cl= GIVEN MOLECULES / AVOGADRO NUMBER

= 1.51X10^23 / 6.02X10^23= 0.25 MOLES = 1/4 MOLES

Answered by btabasshumyara
1

Answer:

0.25 moles

Explanation:

Atomic weight of NH4CL= (14*1)+(1*4)+(35.5*1)

= 53.5 a.m.u

So, we know that 53.5 gram = 1 mole

And, 6.023 molecules of NH4CL= 1 mole

So, 1.51*10^23 molecules= (1.51*10^23)/(6.023*10^23)=0.25 moles

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