Question

calculate the numbers of moles of ammonia gas form from 4.6 gram of N2​

Answer 1

Answer:

0.32mole

Explanation:

1.6 moles

14gm. / 1mole

4.6gm / 0.32mole

Answer 2

Number of moles of ammonia gas formed from 4.6 grams of N2 is 0.32 moles of ammonia.

Ammonia is prepared from nitrogen and hydrogen by haber's process in which gaseous nitrogen and hydrogen reacts with each other under high temperature and pressure and ammonia gas is produced. The reaction is:-

N2(g) + 3H2(g)--------> 2NH3(g)

Weight of N2 = 14 g

Number of moles in 4.6 grams of N2 = (given weight of the gas)/Molecular weight

Moles of N2 = 4.6/28 = 0.16 moles

According to the equation we have :-

1 mole of nitrogen produces 2 moles of ammonia

So 0.16 mole of nitrogen will give 2*0.16 = 0.32 mole of ammonia gas.

So 4.6 gram of N2 produces 0.32 mole of NH3 gas.