Question

Calculate the nummber of atom of each element in 45g of kclo3.

Answer 1

Answer:

Explanation:

Molecular mass of KClO3= 39+35.5+3×16=122.5

No. of mole of KClO3= 45 g/122.5g = 0.367 mole

0.367 mole of K = 0.367×6.023×$10^{23}$ = 2.2125 × $10^{23}$

0.367 mole of Cl = 0.367×6.023×$10^{23}$ = 2.2125 × $10^{23}$

0.367 x 3  mole of O = 3×0.367×6.023×$10^{23}$ = 6.631 × $10^{23}$