Chemistry, asked by Anushree11, 1 year ago

calculate the % of Fe in FeSO4.7H2O
(Fe is 56,S is 32,O is 16,H is 1)

Answers

Answered by drbabbarprashant

apply simple mathematics
total molar weight of compound is 278 calculated by adding molecular mass of every atom
so
56/278 ×100 is about 20%

drbabbarprashant: because we have to find out the percentage

drbabbarprashant: and total weight of compound is 278

Anushree11: bt y only 56 y nt othr no.

drbabbarprashant: because molecular weight if iron is 56

drbabbarprashant: if we were given to find out percentage of S then we ll calculate as 32/278 multiplied by 100

drbabbarprashant: its as simple as that

drbabbarprashant: i hope u understood if not then tell me

Anushree11: ok understood

Anushree11: thnks

drbabbarprashant: wc

Answered by Anonymous

Total weight
56+32+64+14+16*7=278

% FE=56*278/100==155.68

Anonymous: srry

drbabbarprashant: how can percentage be more than 100

drbabbarprashant: haha

Anonymous: 56/278*100..mistaken

drbabbarprashant: yeah this is correct

Anonymous: % FE=56/278*100==20.14

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