Question

CALCULATE THE %OF NITROGEN IN UREA (NH2CONH2)​?

Answer 1

Molecular weight of NH₂CONH₂ is 60g

% of nitrogen = (Weight of nitrogen in compound / Weight of compound) × 100
= ((2 × 14) / 60) × 100
= 46.67%

% of nitrogen in urea is 46.67%

Answer 2

Answer:

The percentage of Nitrogen in urea is 46.7%.

Explanation:

The chemical formula of urea is $\mathrm{NH}_{2}-\mathrm{CO}-\mathrm{NH}_{2}$.  

Here the molar mass of:

N =  14 u

C = 12 u

O = 16 u

H = 1 u

Molar mass of $\mathrm{NH}_{2}-\mathrm{CO}-\mathrm{NH}_{2}=(2 \times 14)+12+16+(4 \times 1)=60$

Mass percentage of $\mathrm{N}=(\text { Mass of } \mathrm{N} \text { in urea } / \text { Total mass }) \times 100$

Plug the values to calculate the mass percentage of N:

$\bold{\mathrm{N} \%=(28 / 60) \times 100=46.7 \%}$