Question

calculate the %of oxygen in AL2 (SO4)3 (Atomic mass Al-12,O16,S-32)​

Answer 1

Answer:

There is 61.538% oxygen in Al2(SO4)3.

Explanation:

Wt. Of oxygen in the compound=12*16 = 192 amu.

Total Wt. Of the compound=2*12+3*32+12*16=312 amu.

Thus, percent of oxygen=Wt of oxygen/total Wt. Of compound *100

=192/312 * 100=61.538%. Ans.

Answer 2

The percentage of oxygen in $Al_2(SO_4)_3$ is 56%

Explanation:

The percentage composition of oxygen in $Al_2(SO_4)_3$

Atomic mass of aluminium= 27 g/mol

Atomic mass of oxygen = 16 g/mol

Atomic mass of sulphur = 32 g/mol

Molecular mass of $Al_2(SO_4)_3$  = $2\times 27+3\times 32+12\times 16=342g/mol$

Percentage of an element in a compound:

$\frac{\text{Number of atoms of element}\times \text{Atomic mass of element}}{\text{molecular mass}}\times 100$

Percentage of oxygen:

$\frac{12\times 16g/mol}{342g/mol}\times 100=56\%$

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