Question

calculate the % of relative abundance of B 10and B 11 if its average atomic mass is 10.804 amu​

Answer 1

Answer:

Explanation:

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Answer 2

$\huge\fbox\blue{Question}$

Calculate the % relative abundance of B -10 and B -11, if its average atomic mass is 10.804 amu.

$\huge\mathfrak\red{Answer:- \:80.4\%}$

$\huge\fbox\blue{Solution}$

Let % Relative abundance of B-10 =x

Let % Relative abundance of B-11 = (100 - x)

Average atomic mass of Boron:

$= \frac{Mass \: of \: 1st \: Isotope \times \: Abundance \: of \: 1st \: Isotope \: \times \: Mass \: of \: 2nd \: Isotope \: \times \: Abundance \: of \: 2nd \: Isotope }{100}$

$10.804 = \frac{10x + 11 \: (100 - x)}{100}$

$10.804 = \frac{10x \: + \: 1100 - 11 x)}{100}$

⇒ 10.804 × 100 = 1100 - x

⇒ 1080.4 = 1100 - x

⇒ x = 1100 - 1080.4

⇒ x = 196%

% Relative abundance of B-10

⇒x=19.6%

% Relative abundance of B-11 ⇒100-x

⇒ 100 - 9.6

⇒ y = 80.4 %

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