Chemistry, asked by dimaria, 1 year ago

calculate the % of the naturally occuring isotopes 35Cl and 37Cl that accounts for the atomic mass of chlorine taken as 35.5u with solutions please thanku

Answers

Answered by honeysvb
0
let the % of 35Cl is x%
let the % of 37Cl is (100-x)%
given atomic mass of Cl is 35.5u
so, [35(x)+37(100-x)]/100 = 35.5
       35x+3700-37x = 3550
       -2x = 3550-3700
        2x = 150
          x = 75
    100-x = 100-75 = 25
therefore, % of 35Cl is 75% in nature and % of 37Cl is 25% in nature

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