Question

Calculate the opposing force required to reduce the velocity from 0.85m/sec to 0.25m/sec of a body of a mass 5kg in 0.03sec.​

Answer 1

Answer:

Given,

Initial Velocity (u) = 0.85 m/s

Final Velocity (v) = 0.25 m/s

Mass (m) = 5 kg

Time (t) = 0.03 s

Acceleration (a) = v-u/t

= 0.25-0.85/0.05

= -0.6/0.05 m/s²

= -12 m/s²

Retardation = 12 m/s²

Opposing force = ma

= 5*12 N

= 60 N

I hope this helps.

Answer 2

Explanation:

force = mass × acceleration

since the in acceleration the velocity going to decrease . then we take acceleration in negative.

force = mass × (-(Final velocity - initial velocity) )/ time taken

force = 5 × (-0.25+0.85)/0.03

=5 × (0.6)/(0.03)

= 5× 20

force = 100 N

Ans.

I hope this will help you..