Calculate the orbital period of the electron in the first excited state of h - atom ?
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by simplifying formula after putting values of constants
we get
v¹ = 2.18 x {{10}^{6}} m/s
and V = v¹ / n
For first excited state n = 2
so V = (2.18 x {{10}^{6}})/2 m/s
V = 1.09 x {{10}^{6}} m/s
time period = 2 π R°/ V
(radius taken for orbital n=2)
R° = n²r ( r =52.9 pm)
so T = 2× 2² ×52.9 ×10-¹²/ 1.09 x {{10}^{6}}
T =1.22 × 10^-15 seconds....
(short method given in pictures for better understanding)
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