Calculate the osmotic pressure (in atm) of a solution 0.1 M NaCl at 25 Co. Assume a 100% ionization solute.
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Answer:
π=iCRT
4.92=i×0.1×0.0821×300
⇒i=1.99
α=
n−1
i−1
α=
3−1
1.99−1
=
2
0.99
=0.49
Percentage ionization =49%
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