Question

calculate the osmotic pressure of 5 percent solution of glucose at 300k


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Answer 1

Answer:

Explanation:

The osmotic pressure of the 5% glucose solution is 6.97 atm

Answer 2

The osmotic pressure of a 5 percent solution of glucose at 300 K is 6.84 atm.

Given: 5 percent solution of glucose at 300 K.

To Find: The osmotic pressure of 5 percent solution of glucose at 300 K.

Solution:

• We know that 5 % solution of glucose means we are given 5 g of sugar in a solution of 100 ml.
• So, the volume of the solution is 100 ml or 0.1 L.
• The osmotic pressure of a solution can be found by the formula,

                π = ( w × R × T ) / ( M × V )                                         ...(1)

Where π = osmotic pressure, w = given mass of solute, R = universal gas constant, T = temperature, M = molecular mass of solute, V = volume.

Coming to the numerical, we are given;

w = 5 g, M = 180 g, R = 0.0821 L.atm / K / mol, T = 300 K, V = 0.1 L.

Putting the respective values in (1), we get;

                 π = ( w × R × T ) / ( M × V )

            ⇒  π = ( 5 × 0.0821 × 300 ) / ( 180 × 0.1 )

            ⇒  π = 123.15 / 18

            ⇒  π = 6.84 atm

Hence, the osmotic pressure of a 5 percent solution of glucose at 300 K is 6.84 atm.

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